Introduction Find the difference between the square of the sum and the sum of the squares of the first n natural numbers. The square of the sum of the first ten natural numbers is $(1 + 2 + … + 10)^2 = 55^2 = 3025$. The sum of the squares of the first ten natural numbers is $1^2 + 2^2 + … + 10^2 = 385$. Hence the difference between the square of the sum of the first ten natural numbers and the sum of the squares of the first ten natural numbers is $3025 - 385 = 2640$.